(x−xc)2+(y−yc)2+(z−zc)2=R2 (1,0,0):(1−xc)2+(0−yc)2+(0−zc)2=R2
(0,1,0):(0−xc)2+(1−yc)2+(0−zc)2=R2
(0,0,1):(0−xc)2+(0−yc)2+(1−zc)2=R2
xc2−2xc+1+yc2+zc2=R2xc2+yc2−2yc+1+zc2=R2xc2+yc2+zc2−2zc+1=R2
xc=yc=zc3xc2−2xc+1=R2 (1/3,1/3,1/3):
(31−xc)2+(31−yc)2+(31−zc)2=R2 Then
3(31−xc)2=3xc2−2xc+1
1−23xc+3xc2=3xc2−2xc+1
xc=31=33=yc=zc
R2=3(31)2−2(31)+1=2−32
C(33,33,33),R=2−32
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