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4. Factoris e: 27 p^3 -1/216-9/2p^2+1/4p
8. You receive a prescription for a drug to be given in a dose of 5 mg/m2. Calculate the dose of the drug for a patient with a BSA of 1.25m2. Solve the problem using both ratio and proportion and dimensional analysis.
if a=0.5 and b=0.4 then what is 4a-b , b+4, 4(a+b-1) , 6a+b b-2a+1 a squared + b
a rural population (given in thousands) is thought to decline according to the equation p=15e^(-0.1t). if t=0 at the beginning of 1998.
1)calculate the numbers in the population at the beginning of 1990,2000,2016.
2) graph population up to 2050.
3)calculate the number of years it will take for the population to decline to 10000.
Sketch: y=1/36(x^2−6)^2(x+1)^2(x^2−3x−4)(3−2x)^3(x^2+1)(x^2−4x−1)

Find y int, zeros, and multiplicities?
Additional Mathematics

Simplify or express a logarithmic expression in terms of an unknown value.

GIven that lg 2=p , and lg 3 = q , express the following in terms of p and q.

(a) lg 54
(b) lg squareroot 120
(c) lg 3and 3/4
A VSAT satellite connection provides the community in Tokmak with a download speed of up to 1.0 Mbps and an upload speed of up to 512 kbps. How much time (in minutes) will it take to
a.download
b.upload a 3.2 MB photograph?
Give all your answers to 3 significant figures
Please show all working out, plus long figures so it can be put into a word document.
the parabola at midnight on the x-y axis keeping des moines at the origin and label the location of columbus memphis and louisville on the graph.

Columbia is 550 miles east and 80 miles south of des moines
memphis is 90 miles east and 430 miles south of des moines
louisville is 420 miles east and 230 miles south of des moines
A satellite connection provides the community in timbuktu with a download speed of up to 1.0 Mbps and an upload speed of up to 512 kbps.

How much time (in minutes) will it take to

a.download
b.upload

a 3.2 MB photograph?

Answers to 3 significant figures please.
(a) Write the first 5 terms of the following sequences

(i) a1= 4
an= an-1 + 4

(ii) a1= -1
an= an-1 - 2

(iii) a1= 0.25
an= an-1 + 0.5

(iv) a1= 1
an= n.an-1
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