Answer on Question #60016 – Math – Algebra
Question
Simplify or express a logarithmic expression in terms of an unknown value.
Given that lg 2 = p \lg 2 = p lg 2 = p , and lg 3 = q \lg 3 = q lg 3 = q , express the following in terms of p p p and q q q .
(a) lg 54 \lg 54 lg 54 ;
(b) lg \lg lg squareroot 120;
(c) lg 3 \lg 3 lg 3 and 1 4 \frac{1}{4} 4 1 .
Solution
(a)
lg 54 = lg 2 ⋅ 27 = lg 2 + lg 27 = p + lg 3 3 = p + 3 lg 3 = p + 3 q . \lg 54 = \lg 2 \cdot 27 = \lg 2 + \lg 27 = p + \lg 3^3 = p + 3 \lg 3 = p + 3q. lg 54 = lg 2 ⋅ 27 = lg 2 + lg 27 = p + lg 3 3 = p + 3 lg 3 = p + 3 q .
(b)
lg 120 = lg 12 0 1 / 2 = 1 2 lg ( 5 ⋅ 3 ⋅ 8 ) = 1 2 ( lg 5 + lg 3 + lg 8 ) = 1 2 ( lg 5 + q + lg 2 3 ) = 1 2 ( lg 5 + q + 3 p ) . \lg \sqrt{120} = \lg 120^{1/2} = \frac{1}{2} \lg (5 \cdot 3 \cdot 8) = \frac{1}{2} (\lg 5 + \lg 3 + \lg 8) = \frac{1}{2} (\lg 5 + q + \lg 2^3) = \frac{1}{2} (\lg 5 + q + 3p). lg 120 = lg 12 0 1/2 = 2 1 lg ( 5 ⋅ 3 ⋅ 8 ) = 2 1 ( lg 5 + lg 3 + lg 8 ) = 2 1 ( lg 5 + q + lg 2 3 ) = 2 1 ( lg 5 + q + 3 p ) .
(c)
lg 3 3 4 = lg 12 + 3 4 = lg 15 4 = lg 15 − lg 4 = lg ( 5 ⋅ 3 ) − lg 2 2 = lg 5 + lg 3 − 2 lg 2 = lg 5 + q − 2 p . \lg 3\frac{3}{4} = \lg \frac{12 + 3}{4} = \lg \frac{15}{4} = \lg 15 - \lg 4 = \lg (5 \cdot 3) - \lg 2^2 = \lg 5 + \lg 3 - 2 \lg 2 = \lg 5 + q - 2p. lg 3 4 3 = lg 4 12 + 3 = lg 4 15 = lg 15 − lg 4 = lg ( 5 ⋅ 3 ) − lg 2 2 = lg 5 + lg 3 − 2 lg 2 = lg 5 + q − 2 p .
Answer: (a) p + 3 q p + 3q p + 3 q ; (b) 1 2 ( lg 5 + q + 3 p ) \frac{1}{2} (\lg 5 + q + 3p) 2 1 ( lg 5 + q + 3 p ) ; (c) lg 5 + q − 2 p \lg 5 + q - 2p lg 5 + q − 2 p .
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