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A reversible chemical reaction combines A and B to produce C and D according to
A+2B\underset{k_2}{\overset{k_1}{\rightleftharpoons}} C+ D. At equilibrium, A, B and C are present in concentrations 1 M, 0.05 M, 500 mM respectively. If the rate constants are k1=2M−2s−1 k1=2M−2s−1 and k2 =1M−1s= −1 k2=1M−1s−1, what is the concentration of D in M at equilibrium? Give the result to three significant figures.
1) 1050 dollar is shared between A,B,C so that B receives 50% more than A, and C receives 25% more than B. How much does each receive?
2) A tank whose base is 2.25m square contains 9000 litres of water. Find the depth of the water.
A 2cm by 2cm square piece of cardboard was cut from bigger square cardboard. The area of the remaining cardboard was 36cm2. If m represents the side of the bigger cardboard which of the following expressions give the area of the remaining piece?
Now, that you have a deeper understanding of the topic, I believe that you are ready to solve the problems below.
Mission Possible
1. The volume V of air remaining in an inflated balloon can be modeled by the function V = 1,000(0.85) where x represents the number of days that have passed since inflating the balloon. What is the reasonable domain for the situation? Explain.
2. The function f(x)=65,000(1.5) can be modeled the population of a city for x, the number of years that have passed since 2010. What inequality represents the reasonable range of the function based on the situation? Explain.
1. Classify the type of linear correlation you might expect with the following pairs of variables.
a. hours of studying for a final exam, grade on final exam
b. students’ average marks, temperature on the day of final exams
c. distances from students’ home to their schools, the time they spend on the school bus each day
d. amounts of television watched per day, scores on a fitness test
e. years without an accident, driving insurance rates
Find basis for the eigenspaces of H
how much do we need to plus in 3 to get five
construct a function table of the following functions using the interval of -5 to 5.
b. J(t)= 1/t^2 - 2t +1
