Answer to Question #92943 in Algebra for kingmosha

Question #92943
Find the gcf and lcm of the following:
(a) 3m^2pq,9mp^2,12mpq,3mn^2

(b) 5a^2b^3,10ab^4,2a^2b^3

(c) (m - n)^2, (m - n)
1
Expert's answer
2019-08-20T14:23:26-0400

(a) Find the GCF and LCM of these sets of expressions: 3m2pq, 9mp2, 12mpq, 3mn2.

Solution: List the prime factors of each.

3m2pq : 3*m*m*p*q

9mp2 : 3*3*m*p*p

12mpq: 3*2*2*m*p*q

3mn2: 3*m*n*n

3*m is the only common factor; therefore, 3*m is the GCF.

Multiply each factor the greatest number of times it occurs in any of the numbers.

3m2pq has two m's and one q,

9mp2 has two 3's and two p's,

12mpq has two 2's,

3mn2 has two n's,

so we multiply m two times, q once, 3 two times, p two times, 2 two times, n two times.

This gives 64m2qp2n2 is LCM, the smallest expression that can be divided evenly by 3m2pq, 9mp2, 12mpq, 3mn2.


(b) Find the GCF and LCM of these sets of numbers: 5a2b3,10ab4, 2a2b3.

Solution: List the prime factors of each.

5a2b3: 5*a*a*b*b*b

10ab4: 2*5*a*b*b*b*b

2a2b3: 2*a*a*b*b*b

a*b3 is the only common factor; therefore, a*b3 is the GCF.

Multiply each factor the greatest number of times it occurs in any of the numbers.

5a2b3: has one 5 and two a's,

10ab4 has one 2 and four b's,

so we multiply 2 once, 5 two times, a two times, b four times.

This gives 10a2b4 is LCM, the smallest expression that can be divided evenly by 5a2b3,10ab4, 2a2b3.


(c) Find the GCF and LCM of these sets of numbers: (m-n)2, (m-n).

Solution: List the prime factors of each.

(m-n)2 : (m-n)*(m-n)

(m-n) : (m-n)

(m-n) is the only common factor; therefore, (m-n) is the GCF.

Multiply each factor the greatest number of times it occurs in any of the numbers. (m-n)2 has two (m-n), and (m-n) has one (m-n), so we multiply (m-n) two times. This gives (m-n)2 is LCM, the smallest expression that can be divided evenly by (m-n)2 and (m-n).


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