Makhayaz weight is 110% of mohammeds weight.the ratio of josephs weight to tumelos weight is 10:11,the ratio of ceciliaz weight to makhayaz weight is 6:7.Ceciliaz weight is 120% of josephs weight,who weighs the least?
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Expert's answer
2012-03-27T09:15:30-0400
Let the Makhayaz's weight be M. Then Mohammed's weight is 1.1M. Let the Joseph's weight be J and Tumelos's weight be T. Then J/T = 10/11. Let the Ceciliaz's weight be C. Then C/M = 6/7. Also, C = 1.2J. So, we've got the system of equations:
C/M = 6/7 ==> C = 6M/7. C = 1.2J ==> J = C/1.2 = 6M/7/1.2 = 5/7 M. J/T = 10/11 ==> T = 11J/10 = 11/10*5/7 M = 55/70 M.
Finally, we've got:
Makhayaz: M Mohammed: 1.1 M Ceciliaz: 6/7 M (≈0.8571 M) Joseph: 5/7 M (≈0.7143 M) Tumelos:& 55/70 M (≈0.7857 M)
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