If p2+48 is equal to -14p then we have the next equation:
p2+48=−14p,
p2+14p+48=0.
To solve this quadratic equation, let's find its discrininant:
D=b2−4ac=142−4⋅1⋅48=196−192=4.
As D>0 the equation has two real distinct roots:
p1=2a−b−D=2−14−2=−8,
p2=2a−b+D=2−14+2=−6.
So, there are two values of p: -8 and -6, such that p2+48 is equal to -14p:
At p=−8:
(−8)2+48=64+48=112=−14⋅(−8).
At p=−6:
(−6)2+48=36+48=84=−14⋅(−6).
Answer: p=-8 and p=-6.
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