The sum of three consecutive integers is 72. Find the integers.
Solution:
Let n - 1 - first consecutive integer
Let n - second consecutive integer
Let n + 1 - third consecutive integer
So, the sum of three consecutive numbers:
(n - 1) + n + (n + 1) = 72
n - 1 + n + n + 1 = 72
3n = 72
n = 24
n - 1 = 23
n + 1 = 25
Check:
(n - 1) + n + (n + 1) = 72
23 + 24 + 25 = 72
72 = 72
Answer:
The three consecutive integers whose sum is 72 are 23, 24, and 25
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