Is not defined
Domain is: x<1 or x>1
Then , y cannot be zero
Range is: f(x)<0 or f(x)>0
2) For x-4=0, x=4, and f(x) cannot be defined
Domain is: x<4 or x>4
Let
y-2, cannot be zero, Therefore y cannot be 2
Range is: f(x)<2 or f(x)>2
3) For, 5x-5=0, implying that x=1, f(x) cannot be defined
Domain is: x<1 or x>1
Let
(5y-1), cannot be zero, Therefore, y, cannot be
Range is:
4) 2x cannot be zero
Domain is: x<0 or x>0
Let
(2y-1), cannot be zero, therefore y cannot be ½
Range is: f(x)<½ or f(x)>½
5) For x²-9=0, x=3 or -3 and f(x) cannot be defined at those points.
Domain is: x<-3 or -3<x<3 or x>3
Let
(1-y) cannot be zero, therefore y cannot be 1
Discriminant cannot be negative, therefore y cannot be greater than ⅓
Range is: f(x)<⅓ or ⅓<f(x)<1 or f(x)>1
Comments
Leave a comment