Answer to Question #232791 in Algebra for ronahmae

Question

Construct a table of valued of function using the interval of -5 to 5.

j(t)=1/(t²-2t+1)

Answer 1

$j(t)=\dfrac{1}{t^2-2t+1}$

$j(t)=\dfrac{1}{(t-1)^2}$

$t\not=1$

Doman: $(-\infin, 1)\cup(1, \infin).$

If we consider the interval $[-5, 5],$ then $t\in[-5, 1)\cup(1, 5].$

$\def\arraystretch{1.5} \begin{array}{c:c} t & y=j(t) \\ \hline -5 & 1/36 \\ \hdashline -4.5 & 4/121 \\ \hdashline -4 & 1/25 \\ \hdashline -3.5 & 4/81 \\ \hdashline -3 & 1/16 \\ \hdashline -2.5 & 4/49 \\ \hdashline -2 & 1/9 \\ \hdashline -1.5 & 4/25 \\ \hdashline -1 & 1/4 \\ \hdashline -0.5 & 4/9 \\ \hdashline 0 & 1 \\ \hdashline 0.5 & 4 \\ \hdashline 0.6 & 25/4 \\ \hdashline 0.7 & 100/9 \\ \hdashline 0.8 & 25 \\ \hdashline 0.9 & 100 \\ \hdashline 1.1 & 100 \\ \hdashline 1.2 & 25\\ \hdashline 1.3 & 100/9 \\ \hdashline 1.4 & 25/4 \\ \hdashline 1.5 & 4 \\ \hdashline 2 & 1 \\ \hdashline 2.5 & 4/9 \\ \hdashline 3 & 1/4 \\ \hdashline 3.5 & 4/25 \\ \hdashline 4 & 1/9 \\ \hdashline 4.5 & 4/49 \\ \hdashline 5 & 1/16 \\ \end{array}$