Answer to Question #227916 in Algebra for Val

Question #227916

1.1 Using graphical method, solve the equation; π‘₯

2

- 3π‘₯ – 4 = 0

1.2 Solve the equation; x

2

- 8x + 7 = 0 using the Quadratic Formula


1
Expert's answer
2021-08-23T07:23:08-0400

1.1 Using graphical method, let solve the equation π‘₯2βˆ’3π‘₯βˆ’4=0.π‘₯^2- 3π‘₯ -4 = 0.

Let us sketch the graph of the function f(x)=π‘₯2βˆ’3π‘₯βˆ’4:f(x)=π‘₯^2- 3π‘₯ -4:




It follows from the graph that the solutions of the equation π‘₯2βˆ’3π‘₯βˆ’4=0π‘₯^2- 3π‘₯ -4 = 0 are x=βˆ’1x=-1 and x=4.x=4.



1.2 Let us solve the equation x2βˆ’8x+7=0x^2- 8x + 7 = 0 using the Quadratic Formula.


Let us find the discriminant:


D=(βˆ’8)2βˆ’4β‹…7=64βˆ’28=36D=(-8)^2-4\cdot 7=64-28=36


We conclude that the solutions are


x1=8+362=8+62=142=7x_1=\frac{8+\sqrt{36}}{2}=\frac{8+6}{2}=\frac{14}{2}=7 and x2=8βˆ’362=8βˆ’62=22=1.x_2=\frac{8-\sqrt{36}}{2}=\frac{8-6}{2}=\frac{2}{2}=1.


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