1.1 Using graphical method, solve the equation; π₯
2
- 3π₯ β 4 = 0
1.2 Solve the equation; x
2
- 8x + 7 = 0 using the Quadratic Formula
1.1 Using graphical method, let solve the equation "\ud835\udc65^2- 3\ud835\udc65 -4 = 0."
Let us sketch the graph of the function "f(x)=\ud835\udc65^2- 3\ud835\udc65 -4:"
It follows from the graph that the solutions of the equation "\ud835\udc65^2- 3\ud835\udc65 -4 = 0" are "x=-1" and "x=4."
1.2 Let us solve the equation "x^2- 8x + 7 = 0" using the Quadratic Formula.
Let us find the discriminant:
"D=(-8)^2-4\\cdot 7=64-28=36"
We conclude that the solutions are
"x_1=\\frac{8+\\sqrt{36}}{2}=\\frac{8+6}{2}=\\frac{14}{2}=7" and "x_2=\\frac{8-\\sqrt{36}}{2}=\\frac{8-6}{2}=\\frac{2}{2}=1."
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