Answer to Question #227663 in Algebra for Santosh

Question

25x^2+4x=100

Answer 1

$25x^2+4x=100$

$25x^2+4x-100=0$

Solve using quadratic equation

$ax^2+bx+c=0$

Using. $x=\frac{-b±\sqrt{b^2-4ac}}{2a}$

$x=\frac{-4±\sqrt{4^2-4(25)(-100)}}{2(25)}$

$x=\frac{-4±\sqrt{16+10000}}{50}$

$x=\frac{-4±\sqrt{10016}}{50}$

$x=\frac{-4±4\sqrt{626}}{50}$

$x_1=\frac{-4-4\sqrt{626}}{50},$

$x_2=\frac{-4+4\sqrt{626}}{50},$

$x_1=-2.0816,$ $x_2=1.9216$