1.1For the X-value 1 the Y-value is
1.2 for the X-value the Y-value is 17
1.3 with how many does the y-value increase for x-value
1.4 at 0 on the x-axis the y-value is 1.explain
1.5 why does the graph form a straight (not a curved line)
Equation : "x-y+1 = 0"
Graph:
(1.1) For x = 1
Put x=1 in above equation , we get
"x-y+1=0\\\\1-y+1=0\\\\y=2"
Hence, for x =1 , y = 2
(1.2) For y = 17
Put y = 17 in above equation , we get
"x-y+1=0\\\\x-17+1=0\\\\x=16"
Hence , for x = 16 ; y = 17
(1.3) From the above graph , we clearly say that for all values of "x\\in R" , the value of y increases.
(1.4) From the equation,
"x-y+1=0"
For x =0
"0-y+1=0\\\\y=1"
So, the graph will cut the y- axis at +1 for x =0
(1.5) Since, the equation is linear equation
and the y value changes by the same amount each time as we change the x value.
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