We have given that,
ba=2−1
a=b(2−1)
We have to find the value of ab(a+3b)a3+2ab+b3
Putting the value of a in the above equation,
We get,
b3(2−1)2+3b3(2−1)b3(2−1)3+2b3(2−1)2+b3
=(2−1)2+(2−1)(2−1)3+(2−1)2+1
After solving we get,
2−232−1
=23
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