perimeter of semi circle=(2+π)r=(2+π)×14=71.9823cm Given, length of rectangle(l) is 2cm more than its width(b).l=2+b perimeter of rectangle=2(l+b) Given, perimeter of semi circle=perimeter of rectangle(2+π)×14=2(l+2+l)(2+π)×14=4(l+1)l+1=4(2+π)×14l=4(2+π)×14−1l=16.9956cm Therefore, width of rectangle is 18.9956cm.Area of the rectangle=lb=16.9956×18.9956=322.8416cm2
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