Question #181688

Solve the following equations. Do a LS = RS check to make sure that your

answer is correct. (8)


b) m + 1/2 + m + 1 /3 ***( / means over)



Expert's answer



m + 1/2 + m + 1 /3

  ⟹  \implies

m+12+m+13m+{1\over 2}+m+{1\over 3}


As I can see in this question

m+12+m+13=0m+{1\over 2}+m+{1\over 3} = 0 .......(1)


2m+56=02m+{5\over 6 } = 0

  ⟹  \implies

m=−512m={-5\over 12 }


If we put this value in (1)


−512+12+−512+13{-5\over 12 } +\frac{1}{2} +{-5\over 12 } +\frac{1}{3}

By calculation this is equals to "0"


  ⟹  LS=RH\implies LS = RH in equation (1).

Hence proved



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