Solve the following equations. Do a LS = RS check to make sure that your
answer is correct. (8)
b) m + 1/2 + m + 1 /3 ***( / means over)
m + 1/2 + m + 1 /3
"\\implies"
"m+{1\\over 2}+m+{1\\over 3}"
As I can see in this question
"m+{1\\over 2}+m+{1\\over 3} = 0" .......(1)
"2m+{5\\over 6 } = 0"
"\\implies"
"m={-5\\over 12 }"
If we put this value in (1)
"{-5\\over 12 } +\\frac{1}{2} +{-5\\over 12 } +\\frac{1}{3}"
By calculation this is equals to "0"
"\\implies LS = RH" in equation (1).
Hence proved
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