Which of the following are possible roots of the function. Select all that apply
5x3 + 19x2- 29x + 5
a. +- 1/5
b. +- 19/29
c. +- 1
d. +- 5
e. +- 0
f. +- 25
g. +- 25/19
h. +- 29/19
Using try and error method
Try (x-1)
x-1 = 0
x= 1
= 5(-1)³ +19(-1)² -29(-1) +5
= 0
Therefore, x-1 is a factor.
To get the other two factors, divide 5x³ +19x² -29x +5 by x-1 using long division.
This will give you 5x² +24x-5
Factorize 5x² +24x -5 =(5x-1)(x+5)
Equate these three factors to zero to give the roots of the function 5x³ +19x² -29x +5
x-1 = 0; x = 1
x+5 = 0; x = -5
5x-1 =0; x = 1/5
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