Based on the Rational Root Theorem, which of the following is not possible roots of the function:
2x2- 9x2+ 13x - 6
a. -3/2
b. 6
c. 1/2
d. -9
Given, the function 2x2-9x2+13x-6.
Simplify the equation,
-7x2+13x-6
In rational root theorem,
anxn+an-1xn-1+...+a0x+a=0 is the equation.
Where an, an-1, ..., a are integers.
The above general equation have a rational solution p/q, where q must divide an and p must divide a0.
Therefore, by rational root theorem,
Then the divisors of 6 are 1, 2, 3 and 6, and the divisors of 7 are 1 and 7.
Thus, if any rational roots exist, they must have a denominator of 1 or 7 and a numerator of 1, 2, 3, or 6, which limits the choices to 1/7, 2/7, 3/7, 6/7 , 1, 2, 3, and 6 and their corresponding negative values.
Therefore, option a, c and d are not possible root of the given function.
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