The bottles of soda sold since June at the food plant can be modeled by function N(m)=10m+300 and does selling per price bottle can be modeled byC(m)=0.6m2-5m+24 where am is the number of months since June
The function of number of bottles sold in month of June is N(m) = 10m +300
Price of each bottle is C(m) = 0.6m2-5m+24
where, m = number of months since June
In June,
number of bottles sold N(1) = (10*1)+300 = 310
price of each bottle C(1) = 0.6(1)2-5(1)+24 = 19.6
In July,
number of bottles sold N(2) = (10*2)+300 = 320
price of each bottle C(2) = 0.6(2)2-5(2)+24 = 16.4
In August,
number of bottles sold N(3) = (10*3)+300 = 330
price of each bottle C(3) = 0.6(3)2-5(3)+24 = 14.4
In September,
number of bottles sold N(4) = (10*4)+300 = 340
price of each bottle C(4) = 0.6(4)2-5(4)+24 = 13.6
In October,
number of bottles sold N(5) = (10*5)+300 = 350
price of each bottle C(5) = 0.6(5)2-5(5)+24 = 14
In November,
number of bottles sold N(6) = (10*6)+300 = 360
price of each bottle C(6) = 0.6(6)2-5(6)+24 = 15.6
In December,
number of bottles sold N(7) = (10*7)+300 = 370
price of each bottle C(7) = 0.6(7)2-5(7)+24 = 18.4
In January,
number of bottles sold N(8) = (10*8)+300 = 380
price of each bottle C(8) = 0.6(8)2-5(8)+24 = 22.4
In February,
number of bottles sold N(9) = (10*9)+300 = 390
price of each bottle C(9) = 0.6(9)2-5(9)+24 = 27.6
In March,
number of bottles sold N(10) = (10*10)+300 = 400
price of each bottle C(10) = 0.6(10)2-5(10)+24 = 34
In April,
number of bottles sold N(11) = (10*11)+300 = 410
price of each bottle C(11) = 0.6(11)2-5(11)+24 = 41.6
In May,
number of bottles sold N(12) = (10*12)+300 = 420
price of each bottle C(12) = 0.6(12)2-5(12)+24 = 50.4
In June of next year,
number of bottles sold N(13) = (10*13)+300 = 430
price of each bottle C(13) = 0.6(13)2-5(13)+24 = 59.4
We can see that the cost of each bottle firstly decreases from June to September and then from October it get increases and the number of bottles sold in each month is increases by 10.
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