Manipulate the above equations in the form of y=mx+c and find the slope and y- intercept as well
1.y=aexp(bx)
2.(y+x)(y-x)=a
3.y=acosx^2+bsinx^2
4.yx^2=c
1.) "y=ae^{bx}"
Taking log on both sides,
"lny=lna+bx\\times lne\\\\lny=lna+bx\\\\lny=bx+lna"
Let lny=Y and x=X
Y = bX + lna
on comparing we get
Slope = b and y-intercept = lna
2.) "(y+x)(y-x)=a"
"y^2-x^2=a"
Let "y^2=Y and \\ x^2=X"
Then, "Y-X=a"
"\\Rightarrow Y=X+a"
On comparing we get
Slope= 1 and y-intercept= a
3.) "y=acos^2x+bsin^2x\\\\"
"\\text{Let cosx=t then}\\\\y=at^2+b(1-t^2)\\\\y=(a-b)t^2+b\\\\y=(a-b)cos^2x+b"
Let y= Y and "cos^2x=X"
Y= (a-b)X +b
On comparing we get
Slope= (a-b) and y-intercept= b
4.)
"yx^2=c\\\\\\text{Taking log on both sides}\\\\ lny+2lnx=lnc\\\\ \\text{Let lny=Y and lnx=X}\\\\Y+2X=lnc\\\\Y=-2X+lnc"
On comparing we get
Slope= -2 and y-intercept= lnc
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