Answer to Question #175680 in Algebra for will

Question

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(3x² + x - 4) - ( 4x - 6 + 8x²)

Answer 1

$To \ find \ the \ difference \ of \ the \ polynomials \\ (3x^2 +x-4)-(4x-6+8x^2)\\ Opening \ the \ parenthesis \ we \ get \\ 3x^2 +x-4 -4x-(-6)-(8x^2 ) \because -a(b+c)=-ab-ac\\$

$3x^2 +x-4-4x+6-8x^2\because (-1)(ax)=-ax\\ Regrouping \ the \ like \ powers\ of \ x\ we \ get \\ 3x^2-8x^2+x-4x-4+6=(3-8)x^2+(1-4)x+(-4+6) \\ \because (a+b)x=ax+bx\\ -5x^2 -3x+2\\ \therefore(3x^2+x-4)-(4x-6+8x^2)=-5x^2-3x+2$