on the day a video was posted online, 5 people watched the video. The next day the number of viewers had doubled. Assume the number of viewers continues to double each day. what strategy would you use to find the first day when more then 20,000 people will see the video(if the trend continues)
"Tn=ar^{(n-1)}"
"20000=5(2^{(n-1)})"
"4000=2^{(n-1)}"
"n=12.95678428"
n is approximately 13 days
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