Question #173099

The eight term of a geometrical progression is –7/32. Find it's common ratio if it's first term is 28.


1
Expert's answer
2021-03-22T10:11:55-0400
b8=b1q7b_8=b_1q^7

Given b1=28,b8=732b_1=28, b_8=-\dfrac{7}{32}


732=28q7-\dfrac{7}{32}=28q^7

q7=1128q^7=-\dfrac{1}{128}

q=12q=-\dfrac{1}{2}

The common ratio of the geometrical progression is 12.-\dfrac{1}{2}.



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