Answer to Question #152867 in Algebra for O.Weerasinghe

Question #152867
2- |x+1|<|2x - 3| Solve the problem with the steps and mark the answers on a chart
1
Expert's answer
2020-12-28T14:43:21-0500
x+1=0=>x=1x+1=0=>x=-1

2x3=0=>x=322x-3=0=>x=\dfrac{3}{2}


If x<1:x<-1:


2+x+1<2x+3=>3x<0=>x<02+x+1<-2x+3=>3x<0=>x<0

Then x<1x<-1


If 1x<3/2:-1\leq x<3/2:


2x1<2x+3=>x<22-x-1<-2x+3=>x<2

Then 1x<3/2-1\leq x<3/2


If x3/2:x\geq3/2:


2x1<2x3=>3x>4=>x>4/32-x-1<2x-3=>3x>4=>x>4/3

Then x>3/2x>3/2

Therefore


x(,)x\in(-\infin, \infin)


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