Answer to Question #121601 in Algebra for Jeraldine

Question

Joe is going to the water slides and needs to figure out which deal is better. He can pay $30 to go on the water slides as much as he wants, or he can pay $18 to get in, plus an additional $3 per trip down the water slides. If Joe goes on a certain number of trips down the water slides, the two options are equivalent in terms of cost. What is the cost? How many trips is that?

Answer 1

Let C represent the total cost of each deal 

Let T be the number of trips down the water slide 

 

J = 30    for the 1st deal since the cost is the same regardless of how much she rides 

$C = 18 + T$ for the 2nd deal 

 

To find when the two costs are equal set them equal to each other and solve for T 

 

$30 = 18 + T$

T = 12 trips 

 

The cost must be $30 since that is the only cost possible for the 1st deal