If "\\alpha=-4+5i" is the root of the quadratic equation "f(x)=0," then "\\beta=-4-5i" is also the root of the quadratic equation "f(x)=0."
"\\alpha=-4+5i, \\beta=-4-5i"
Hence
"f(x)=a(x-(-4+5i))(x-(-4-5i))"
"\\alpha+\\beta=-4+5i-4-5i=-8=-{b\\over a}"
"\\alpha\\cdot\\beta=(-4+5i)\\cdot(-4-5i)=(-4)^2+(5)^2=41={c\\over a}"
"f(x)=ax^2 +8ax+41a, a\\not=0"
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