Question

Find the product of ( 3-i 4,

-4 3+i )

and ( 2 5-2i

-5 - 2i 2 )

Answer 1

Doing dot product of $((3- \frac{i}{4}),(\frac{-4}{3} + i))$ and $((\frac{2}{5} - 2i),(\frac{-5-2i}{2}))$

Product = $((3- \frac{i}{4}),(\frac{-4}{3} + i))$ * $((\frac{2}{5} - 2i),(\frac{-5-2i}{2}))$

=( $(3- \frac{i}{4})$ * $(\frac{2}{5} - 2i)$ , $(\frac{-4}{3} + i)$ * $(\frac{-5-2i}{2})$ )

solving it we get,

= $((\frac{7}{10} - \frac{61}{10}i) , (\frac{7}{3} - \frac{7}{6}i))$

since $i^{2} = -1$