Answer to Question #118978 in Algebra for Max

Question #118978
Find the product of ( 3-i 4,
-4 3+i )
and ( 2 5-2i
-5 - 2i 2 )
1
Expert's answer
2020-06-03T16:11:06-0400

Doing dot product of ((3i4),(43+i))((3- \frac{i}{4}),(\frac{-4}{3} + i)) and ((252i),(52i2))((\frac{2}{5} - 2i),(\frac{-5-2i}{2}))


Product = ((3i4),(43+i))((3- \frac{i}{4}),(\frac{-4}{3} + i)) * ((252i),(52i2))((\frac{2}{5} - 2i),(\frac{-5-2i}{2}))


=( (3i4)(3- \frac{i}{4}) * (252i)(\frac{2}{5} - 2i) , (43+i)(\frac{-4}{3} + i) * (52i2)(\frac{-5-2i}{2}) )


solving it we get,


= ((7106110i),(7376i))((\frac{7}{10} - \frac{61}{10}i) , (\frac{7}{3} - \frac{7}{6}i))


since i2=1i^{2} = -1



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