1) (3−4i)×(−43+i)(3-4i)\times (-43+i)(3−4i)×(−43+i)
=3×−43+3i−4i×−43−4i2=−125+175i= 3\times-43+3i-4i\times-43-4i^{2}= -125+175i=3×−43+3i−4i×−43−4i2=−125+175i
Answer : 25(−5+7i)25(-5+7i)25(−5+7i)
2) (25−2i)×(−5−22i)(25-2i)\times(-5-22i)(25−2i)×(−5−22i)
=25×−5+25×−22i−2i×−5+44i2=−169−540i= 25 \times -5 + 25 \times -22i - 2i \times -5 + 44i^{2} = -169 -540 i=25×−5+25×−22i−2i×−5+44i2=−169−540i
Answer : -169 -540 i
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