"f(x)= \\cfrac{3}{x^2}+2" .
Given that x is in the denominator, it cannot be equal to 0.
So, the domain of this function is "x \\in (- \\infty, 0)\u222a(0; + \\infty)".
The value "\\cfrac{3}{x^2}" could not be less than 0 because "x^2 >0" for all x.
The value "\\cfrac{3}{x^2}" could not be equal 0.
All of theese means that value "\\cfrac{3}{x^2}+2 > 2" for all x.
So, the range of "f(x)" is "(2, + \\infin )" .
Answer: Domain is "(- \\infty, 0)\u222a(0, + \\infty)" , range is "(2, + \\infin )" .
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