f(x)=x23+2 .
Given that x is in the denominator, it cannot be equal to 0.
So, the domain of this function is x∈(−∞,0)∪(0;+∞).
The value x23 could not be less than 0 because x2>0 for all x.
The value x23 could not be equal 0.
All of theese means that value x23+2>2 for all x.
So, the range of f(x) is (2,+∞) .
Answer: Domain is (−∞,0)∪(0,+∞) , range is (2,+∞) .
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