By definition, the inverse element is
p∗p−1=p−1∗p=e where e is an identity element.
For the convenience of the solution, we will denote p−1≡q .
Then,
p∗q=p2−q2−2pq=e We will consider this as an equation for a variable q .
q2+2pq+(e−p2)=0D=(2p)2−4⋅(e−p2)=4p2+4p2−4e=8p2−4eq1=2−2p+8p2−4e=−p+2p2−eq2=2−2p−8p2−4e=−p−2p2−e Check result
p∗q1=p2−q12−2pq1==p2−(2p2−e−p)2−2p(2p2−e−p)==p2−(2p2−e−2p2p2−e+p2)+2p2−2p2p2−e==p2−3p2+e+2p2p2−e+2p2−2p2p2−e=e Conclusion,
p⟶p−1=2p2−e−p ANSWER
p⟶p−1=2p2−e−p
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