We look at this problem from two perspective.
Case 1 (b=0)
If b=0 then a+b = a. And since a is a unit of R, we can conclude that a+b=a is a unit of R.
Case 2 (
Since a is a unit, let c be the inverse of a.
In order to show that a+b is a unit, it suffices to show that 1+bc is a unit.
Given that , we have that because
Also,
But
That is 1+bc is a unit. Hence, a+b is a unit.
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