Prove that every field is artinian.Deduce that Q is artinian.
Let us prove that every field is Artinian. Recall that an Artinian ring is a ring that satisfies the descending chain condition on ideals, i.e. for any decreasing sequence of right ideals "I_1\\supset I_2\\supset\\ldots" there exists a natural number m such that "I_m=I_{m+1}=\\ldots" .
Taking into account that each field "F" contains exactly two ideals: "F" and "O=\\{0\\}", we conclude that for each descending chain of ideals there are two possibilites:
1) Each ideal in a chain is equal to "F".
2) There exists an ideal "I_m" that is equal to "O". Since we consider only descending chains, "I_k=O" for every integer "k>m".
We conclude that in each case a field satisfies the descending chain condition on ideals, and hence each field is Artinian.
Since "(\\mathbb Q,+,\\cdot)" is a field, it is Artinian.
Comments
Leave a comment