Question #162935

Find a binary function * on Q such that phi is an isomorphism mapping <Q, +> with <Q , *) and give the identity element for *. The map is phi : Q --> Q is given by phi(x)=3x-1 for x is an element of Q


1
Expert's answer
2021-02-24T07:29:27-0500

Solution:

Given an isomorphism mapping, i.e., one-to-one and onto map ϕ:QQ\phi: {Q} \rightarrow {Q} defined as ϕ(x)=3x1\phi(x)=3 x-1 .

Note that for any xQx \in {Q} , we have ϕ(x+13)=x\phi\left(\frac{x+1}{3}\right)=x

Here we find out what aba * b equals.

From the above line, and from the fact that the condition ϕ(x)ϕ(y)=ϕ(x+y)\phi(x) * \phi(y)=\phi(x+y) must hold, we have,

ab=ϕ(a+13)ϕ(b+13)=ϕ(a+13+b+13)=ϕ(a+b+23)=3(a+b+23)1=a+b+1a * b=\phi\left(\frac{a+1}{3}\right) * \phi\left(\frac{b+1}{3}\right)=\phi\left(\frac{a+1}{3}+\frac{b+1}{3}\right)=\phi\left(\frac{a+b+2}{3}\right)=3( \frac{a+b+2}{3})-1=a+b+1

Therefore our binary operation is ab=a+b+1a * b=a+b+1 .

For this particular binary operation the element 1Q-1 \in {Q} is the identity because 1a=1+a+1=a-1 * a=-1+a+1=a .


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