Answer to Question #162933 in Abstract Algebra for K

Question #162933

Give a proof that the associative property is a structural property. (Start with two isomorphic structures, let the operation on one be associative and show that its image must also be associative).


1
Expert's answer
2021-02-12T18:11:15-0500

Let (G,)(G,*) and (K,)(K,\circ) be two isomorphic structures, and the operation * on GG is associative. Let us show that the operation \circ on KK is also associative. Let ψ:GK\psi: G\to K be an isomorphism, and a,b,cKa',b',c'\in K be arbitrary. Since ψ\psi is surjection, there exists a,b,cGa,b,c\in G such that a=ψ(a),b=ψ(b),c=ψ(c).a'=\psi(a), b'=\psi(b), c'=\psi(c). It follows that

a[bc]=ψ(a)[ψ(b)ψ(c)]=ψ(a)ψ(bc)=ψ(a(bc))=ψ((ab)c)=ψ(ab)ψ(c)=[ψ(a)ψ(b)]ψ(c)=[ab]ca'\circ[b'\circ c']=\psi(a)\circ[\psi(b)\circ \psi(c)]=\psi(a)\circ\psi(b*c)=\psi(a*(b*c))= \psi((a*b)*c)=\psi(a*b)\circ\psi(c)=[\psi(a)\circ\psi(b)]\circ\psi(c)=[a'\circ b]'\circ c'

Therefore, the operation \circ on KK is also associative, and  the associative property is a structural property.



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