Question #144414

Write out a complete Cayley table for D3.is D3 abelian?


1
Expert's answer
2020-11-17T06:39:27-0500


For our triangle ABC I note:

  1. id - identity transformation
  2. Rot 120 - rotation by 120 degrees around the center of triangle
  3. Rot 240 - rotation by 240 degrees around the center of triangle
  4. Sym - symmetry with respect to the median passing through the point A
  5. Sym 120 - symmetry with respect to the median passing through the point B
  6. Sym 240 - symmetry with respect to the median passing through the point C

With these notations our Cayley table goes like this:



In particular we see that D3 is not abelian, as sym×rot120rot120×simsym \times rot120 \neq rot120\times sim .

The easiest way to study D3 is to consider the action of every element on the vertexes of ABC :

  1. id:(A,B,C)(A,B,C)id:(A,B,C)\mapsto (A,B,C)
  2. rot120:(A,B,C)(B,C,A)rot120:(A,B,C)\mapsto (B,C,A)
  3. rot240:(A,B,C)(C,A,B)rot240 : (A,B,C)\mapsto (C,A,B)
  4. sym:(A,B,C)(A,C,B)sym:(A,B,C)\mapsto (A,C,B)
  5. sym120:(A,B,C)(C,B,A)sym120: (A,B,C)\mapsto (C,B,A)
  6. sym240:(A,B,C)(B,A,C)sym240:(A,B,C)\mapsto (B,A,C)

With this interpretation we see that D3S3D_3 \simeq S_3 (group of bijections of a set of 3 elements) and so it is another proof that it is not abelian (as S3S_3 is not abelian).


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