For our triangle ABC I note:
- id - identity transformation
- Rot 120 - rotation by 120 degrees around the center of triangle
- Rot 240 - rotation by 240 degrees around the center of triangle
- Sym - symmetry with respect to the median passing through the point A
- Sym 120 - symmetry with respect to the median passing through the point B
- Sym 240 - symmetry with respect to the median passing through the point C
With these notations our Cayley table goes like this:
In particular we see that D3 is not abelian, as sym×rot120=rot120×sim .
The easiest way to study D3 is to consider the action of every element on the vertexes of ABC :
- id:(A,B,C)↦(A,B,C)
- rot120:(A,B,C)↦(B,C,A)
- rot240:(A,B,C)↦(C,A,B)
- sym:(A,B,C)↦(A,C,B)
- sym120:(A,B,C)↦(C,B,A)
- sym240:(A,B,C)↦(B,A,C)
With this interpretation we see that D3≃S3 (group of bijections of a set of 3 elements) and so it is another proof that it is not abelian (as S3 is not abelian).
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