Let "G" be any group such that "|G|=44=2^2\u00d711" .
As "11\\mid 44 \\ \\text{and} \\ 11^2 \\nmid 44" therefore "G" has a sylow 11-subgroup .
Let "n" be the number of sylow 11-subgroup then
"n\\equiv 1 \\ mod (11)" and "n\\mid 4" .
Therefore , "n=1,2 \\ or \\ 4" .
But "n=1" is the only solution of the congruence "n\\equiv 1 \\ mod (11)"
Hence "G" has only one sylow 11-subgroup.
Again we known that only one sylow p-subgroup are Normal.
Therefore sylow 11-subgroup is Normal in "G" .
Hence any group of order 44 has a proper normal subgroup.
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