The given ring is "R=\\Z[\\sqrt{-2}]" .
Using this ring ,we have to show
1.The quotient ring of a UFD need not be UFD.
2.An irreducible elements of a UFD need not be a prime.
As we Know that ,"R" is a Euclidean domain.
Again, every Euclidean domain is PID and every PID is UFD.
Hence,"R" is a UFD.
Now consider the ideal ,
"I=<6>=\\{ 6(a+b\\sqrt{-2}):(a+b\\sqrt{-2})\\in R \\}" .
Then ,
clearly,
"2+I,3+I\\in \\frac{R}{I}"but,"(2+I)(3+I)=6+I=I" .
Hence,"\\frac{R}{I}" is not a integral domain.
Therefore, it is not a unique factorization domain.
Since, To become a UFD ,It must be a integral domain .
2. As "R" is a PID ,so every irreducible elements is a prime.
Hence, the question is wrong in this case.
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