Question #103848
Check whether the sequence, {Sn} where

Sn=1/1!+1/3!+1/5!+....1/(2n+1)!
Is convergent or not.
1
Expert's answer
2020-02-27T09:44:35-0500

S=11!+13!+15!+...+1(2n+1)!+...S=\frac{1}{1!}+\frac{1}{3!}+\frac{1}{5!}+...+\frac{1}{(2n+1)!}+...

apply the d'Alembert ratio test to

an=1(2n+1)!,an+1=1(2n+3)!,a_n=\frac{1}{(2n+1)!},\\ a_{n+1}=\frac{1}{(2n+3)!},\\

consider

limnan+1an=limn(2n+1)!(2n+3)!==limn(2n+1)!(2n+1)!(2n+2)(2n+3)==limn1(2n+2)(2n+3)=0<1.lim_{n\mapsto \infty} \frac{a_{n+1}}{a_n}=lim_{n\mapsto \infty} \frac{(2n+1)!}{(2n+3)!}=\\ =lim_{n\mapsto \infty} \frac{(2n+1)!}{(2n+1)!(2n+2)(2n+3)}=\\ =lim_{n\mapsto \infty} \frac{1}{(2n+2)(2n+3)}=0<1.

Since the limit value 0 is less than 1, the series is convergent.


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