Question #102206
Given that x*y=1+x+y, show wheather the binary operation is associative algebrically
1
Expert's answer
2020-02-04T08:40:25-0500

A binary operation \cdot is associative when (xy)z=x(yz)(x \cdot y) \cdot z = x \cdot (y \cdot z) for any x,y,zx, y, z .


Suppose we have

(xy)z(x \cdot y) \cdot z

We can replace the binary operation with addition using its definition:

(xy)z=(1+x+y)z=1+(1+x+y)+z(x \cdot y) \cdot z = (1 + x + y) \cdot z = 1 + (1+x+y) +z


Now we can remove parentheses (using associativity of addition), regroup terms (using commutativity of addition) and put parentheses where we want (using associativity of addition once again):

1+(1+x+y)+z==1+1+x+y+z==1+x+1+y+z==1+x+(1+y+z)1 + (1 + x + y) + z = \\ =1 + 1 + x + y + z = \\ = 1 + x + 1+y +z = \\ =1 + x + (1+y+z)

1+y+z=yz1+y+z = y \cdot z by definition of this binary operation.

1+x+(1+y+z)=1+x+(yz)1+ x + (1+y+ z) = 1+x+(y \cdot z)

1+x+(yz)=x(yz)1+x+(y \cdot z) = x \cdot (y \cdot z) by definition of our binary operation.


We proved that (xy)z=x(yz)(x \cdot y) \cdot z = x\cdot (y \cdot z) which means we proved that the binary operation is associative algebraically. What was to be shown.


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