The mean annual cost of automobile insurance is R95. Assume that the population standard deviation is R14. What is the probability that a simple random sample of size 30 for automobile insurance policies will have a sample mean less than R90?
Mean = R95, SD = R14 & N = 30
X = (R90 – R95) = -5
P(-5<X) =
Therefore,
Q = 14 /Square root of 30
=14/ 5.4772
= 2.5561
(90 – 95)/2.5561 = - 1.96
Probability is – 1.96
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