Answer to Question #295401 in English for Miona kwamboka

Question

An iron ring of cross section area 6cm is round with a wire of a 100 turns and it has asaw cut of 2mm, calculate the magnetising current required to produce a Flux of 0.1wbs if the mean length of magnetic part is 30cm and relative permiability of iron is 470

Answer 1

Ptotal - Rison thair in right ans: I = 3.49A given Area = 6cm? a 100 turns saw (ut = 8 mm calcarlate the magnetizing current required to produce &= 0.1 mwb, mean length of magnetic path = 30cm (=>(0.296 0.062 + unX10 x 470 X6X 417 4102 x 6810 4 => 10" (0.002635) 10-4 ब 2411 - flux 8 = 0.1m wb -0.1 *103 wb Number of thens = 100 &= NL 3 100 XI & Relative pesmeability = 470 -Flux Rtotel Rtotas - Riron + Raier Rison- lison (30-2) 103 UGA 6x10-4 Rain= 0.1x10² 101 (0.002635] ( 241 100I 349.35 GIT x 10 x 470x) I = 3.49 27 2x103 -7 do 4IT x 15 7 21 x 66104 25