Question #303448

A piston–cylinder device contains 1.2 kg of nitrogen gas at 120 kPa and 27°C. The gas is now compressed slowly in a polytropic process during which PV1.3 = constant. The process ends when the volume is reduced by one-half. Determine the entropy change of nitrogen during this process.


1
Expert's answer
2022-02-28T11:09:42-0500

Solution;

From the tables;

R=0.297kJ/kgKR=0.297kJ/kgK

Cv=0.743kJ/kgKC_v=0.743kJ/kgK

From the polytropic relation;

T2T1=(v1v2)n1\frac{T_2}{T_1}=(\frac{v_1}{v_2})^{n-1}

T2=300(2)0.3=369.34KT_2=300(2)^{0.3}=369.34K

Change in entropy;

Δs=m[Cvln(T2T1)+Rln(v2v1)]\Delta s=m[C_vln(\frac{T_2}{T_1})+Rln(\frac{v_2}{v_1})]

Δs=1.2[0.743ln(369.34300)+0.297ln(0.5)]\Delta s=1.2[0.743ln(\frac{369.34}{300})+0.297ln(0.5)]

Δs=0.0616kJ/K\Delta s=-0.0616kJ/K




Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS