Question #50276

Please explain the graph for f=e^x?
1

Expert's answer

2015-01-05T05:30:00-0500

Answer on Question #50276 – Engineering

Please explain the graph for f=exf = e^{\wedge}x ?

Answer:



The graph of y=exy = e^{x} is upward-sloping, and increases faster as xx increases. The graph always lies above the xx -axis but can get arbitrarily close to it for negative xx ; thus, the xx -axis is a horizontal asymptote. The slope of the tangent to the graph at each point is equal to its yy coordinate at that point

Graphs of Exponential Functions

The graph passes through the point (0,1)(0,1)

The domain is all real numbers

The range is y>0y > 0

The graph is increasing

- The graph is asymptotic to the x-axis as x approaches negative infinity

- The graph increases without bound as x approaches positive infinity

- The graph is continuous

- The graph is smooth

MATLAB CODE:


clc,close all,clear all
figure
x=-20:0.1:5
y=exp(x)
xlim([-10 10]),ylim([0 100])
plot(x,y,'o--')
axis equal,grid on
xlabel('x'),ylabel('y')
legend('y=exp(x)')
figure
x=-1:0.1:1.5
y=exp(x)
xlim([-1 1.5]),ylim([0 100])
plot(x,y,'o--')
axis equal,grid on
xlabel('x'),ylabel('y')
legend('y=exp(x)')


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