Question

A vector a of magnitude 8 units has two components. One is perpendicular to a of magnitude 6 units. What is the magnitude of the other component?

Answer 1

Answer on Question #49231 – Engineering – Other

A vector $a$ of magnitude 8 units has two components. One is perpendicular to $a$ of magnitude 6 units. What is the magnitude of the other component?

Solution:

$|\vec{a}| = 8$ unit – magnitude of the vector;

$a_1 = 6$ – first component of the fecto®

$a_2$ – second component of the fecto®;

Using Pythagorean theorem:

$$u_2 = \sqrt{|u|^2 + u_2^2} \sqrt{|u|^2 + u_1^2} = \sqrt{8^2 + 6^2} = 10$$

Answer: second component of the vector is equal to 10.

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