Answer on Question #45757 – Engineering – Other
Obtain the geometric, polar and exponential representations of (i5−1)−1.
Solution:
z=5i−11=(5i−1)(5i+1)5i+1=−25−15i+1=−265i+1=−261−265iGeometric representation = x + yi

Polar representation:
r=x2+y2=(−261)2+(−265)2=6761+67625=67626=261φ=atan(−261−265)−π=atan5−πz=r(cosφ+isinφ),r=∣z∣z=261(−261+i(2625))z=261(cos(atan5−π)+isin(atan5−π))
Exponential representation:
z=261ei(atan5−π)z=reiφ
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