Answer to Question #224613 in Engineering for Papi Chulo

Question

A car of length 5 m is being driven parallel alongside a 100 m long train at the same

speed. The front of the car is 10 m behind the rear of the train. At the instant the train

decelerates at 0.4 ms² the car accelerates at 0,15 ms². How long will it take for the rear

of the car to pass the front of the train?

Answer 1

$$5+10+100+vt-0.5(0.4)t^2=vt+0.5(0.15)t^2\\t=20.45\ s$$