Answer to Question #195357 in Engineering for Saim

Question #195357

A negative charge -q is fixed to one corner of a rectangle, as shown in figure 3. What positive charge must be fixed to corner A and what positive charge must be fixed to corner B, so the total electric field at the remaining corner is zero? Express your answer in terms of q.



1
Expert's answer
2021-05-21T11:37:01-0400
"k\\frac{q}{2a^2}-k\\frac{q'}{2a^2}-k\\frac{q'}{2a^2}=0\\\\q'=0.5q"


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