3. Two pulley 12 in diameter and 20 in diameter is connected by a crossed belt with center distance of 45 in. Find the belt length needed to connect them.
Length of the belt :
L=π(r1+r2)+2x+(r1+r2)2xL = \pi(r_1+r_2)+2x+\frac{(r_1+r_2)^2}{x}L=π(r1+r2)+2x+x(r1+r2)2
L=π(10+6)+2×45+(10+6)245=146L = \pi(10+6)+2\times45+\frac{(10+6)^2}{45} =146L=π(10+6)+2×45+45(10+6)2=146 in
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