4. What is the quality of steam at 248oC and having an enthalpy of 2100 kJ/kg?
T=248oC
h=2100kJ/kg
h=hf+xhfgh=h_f+xh_{fg}h=hf+xhfg
x=h−hfhfgx=\frac{h-h_f}{h_{fg}}x=hfgh−hf
=2100−10731729=\frac{2100-1073}{1729}=17292100−1073
=0.599398
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