Answer to Question #304663 in Mechanical Engineering for Jhay

Question

2. Two parallel shafts connected by rolling cylinders turn in the same direction 150 rpm and 100 rpm respectively. The smaller cylinder is 16 in. in diameter. How far apart are the axes of the shafts?

Answer 1

$\frac{NA}{NB}=\frac{DB}{DA}$

$DB=\frac{NA*DA}{NB}$

$=\frac{150*6}{100}=9in.$

rb=$\frac{db}{2}=\frac{9}{2}=4.5in$

ra=$\frac{DA}{2}=\frac{6}{2}=3in.$

distance between axes = ra+rb

=4.5+3

=7.5 in.